Syntax
#include <string.h> int strcoll(const char *string1, const char *string2);Description
strcoll compares the string pointed to by string1 against the string pointed to by string2, both interpreted according to the information in the LC_COLLATE category of the current locale.
strcoll differs from the strcmp function. strcoll performs a comparison between two character strings based on language collation rules as controlled by the LC_COLLATE category. In contrast, strcmp performs a character to character comparison.
strcoll returns an integer value indicating the relationship between the strings, as listed below: compact break=fit.
Value
Note:
This example compares the two strings passed to main.
#include <stdio.h>#include <string.h>
int main(int argc,char **argv)
{
   int result;
   if (argc != 3) {
      printf("Usage: %s string1 string2\n", argv[0]);
   }
   else {
      result = strcoll(argv[1], argv[2]);
      if (0 == result)
         printf("\"%s\" is identical to \"%s\"\n", argv[1], argv[2]);
      else
         if (result < 0)
            printf("\"%s\" is less than \"%s\"\n", argv[1], argv[2]);
         else
            printf("\"%s\" is greater than \"%s\"\n", argv[1], argv[2]);
   }
   return 0;
   /****************************************************************************
      If the program is passed the following arguments:
      "firststring" "secondstring"
      The output should be:
      "firststring" is less than "secondstring"
   ****************************************************************************/
}
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